3.230 \(\int \frac{(h+i x) (a+b \log (c (d+e x)^n))^3}{f+g x} \, dx\)

Optimal. Leaf size=308 \[ -\frac{6 b^2 n^2 (g h-f i) \text{PolyLog}\left (3,-\frac{g (d+e x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{g^2}+\frac{3 b n (g h-f i) \text{PolyLog}\left (2,-\frac{g (d+e x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{g^2}+\frac{6 b^3 n^3 (g h-f i) \text{PolyLog}\left (4,-\frac{g (d+e x)}{e f-d g}\right )}{g^2}+\frac{6 a b^2 i n^2 x}{g}+\frac{(g h-f i) \log \left (\frac{e (f+g x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{g^2}-\frac{3 b i n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{e g}+\frac{i (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{e g}+\frac{6 b^3 i n^2 (d+e x) \log \left (c (d+e x)^n\right )}{e g}-\frac{6 b^3 i n^3 x}{g} \]

[Out]

(6*a*b^2*i*n^2*x)/g - (6*b^3*i*n^3*x)/g + (6*b^3*i*n^2*(d + e*x)*Log[c*(d + e*x)^n])/(e*g) - (3*b*i*n*(d + e*x
)*(a + b*Log[c*(d + e*x)^n])^2)/(e*g) + (i*(d + e*x)*(a + b*Log[c*(d + e*x)^n])^3)/(e*g) + ((g*h - f*i)*(a + b
*Log[c*(d + e*x)^n])^3*Log[(e*(f + g*x))/(e*f - d*g)])/g^2 + (3*b*(g*h - f*i)*n*(a + b*Log[c*(d + e*x)^n])^2*P
olyLog[2, -((g*(d + e*x))/(e*f - d*g))])/g^2 - (6*b^2*(g*h - f*i)*n^2*(a + b*Log[c*(d + e*x)^n])*PolyLog[3, -(
(g*(d + e*x))/(e*f - d*g))])/g^2 + (6*b^3*(g*h - f*i)*n^3*PolyLog[4, -((g*(d + e*x))/(e*f - d*g))])/g^2

________________________________________________________________________________________

Rubi [A]  time = 0.363952, antiderivative size = 308, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 9, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.31, Rules used = {2418, 2389, 2296, 2295, 2396, 2433, 2374, 2383, 6589} \[ -\frac{6 b^2 n^2 (g h-f i) \text{PolyLog}\left (3,-\frac{g (d+e x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{g^2}+\frac{3 b n (g h-f i) \text{PolyLog}\left (2,-\frac{g (d+e x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{g^2}+\frac{6 b^3 n^3 (g h-f i) \text{PolyLog}\left (4,-\frac{g (d+e x)}{e f-d g}\right )}{g^2}+\frac{6 a b^2 i n^2 x}{g}+\frac{(g h-f i) \log \left (\frac{e (f+g x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{g^2}-\frac{3 b i n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{e g}+\frac{i (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{e g}+\frac{6 b^3 i n^2 (d+e x) \log \left (c (d+e x)^n\right )}{e g}-\frac{6 b^3 i n^3 x}{g} \]

Antiderivative was successfully verified.

[In]

Int[((h + i*x)*(a + b*Log[c*(d + e*x)^n])^3)/(f + g*x),x]

[Out]

(6*a*b^2*i*n^2*x)/g - (6*b^3*i*n^3*x)/g + (6*b^3*i*n^2*(d + e*x)*Log[c*(d + e*x)^n])/(e*g) - (3*b*i*n*(d + e*x
)*(a + b*Log[c*(d + e*x)^n])^2)/(e*g) + (i*(d + e*x)*(a + b*Log[c*(d + e*x)^n])^3)/(e*g) + ((g*h - f*i)*(a + b
*Log[c*(d + e*x)^n])^3*Log[(e*(f + g*x))/(e*f - d*g)])/g^2 + (3*b*(g*h - f*i)*n*(a + b*Log[c*(d + e*x)^n])^2*P
olyLog[2, -((g*(d + e*x))/(e*f - d*g))])/g^2 - (6*b^2*(g*h - f*i)*n^2*(a + b*Log[c*(d + e*x)^n])*PolyLog[3, -(
(g*(d + e*x))/(e*f - d*g))])/g^2 + (6*b^3*(g*h - f*i)*n^3*PolyLog[4, -((g*(d + e*x))/(e*f - d*g))])/g^2

Rule 2418

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*(RFx_), x_Symbol] :> With[{u = ExpandIntegrand[
(a + b*Log[c*(d + e*x)^n])^p, RFx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, d, e, n}, x] && RationalFunct
ionQ[RFx, x] && IntegerQ[p]

Rule 2389

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.), x_Symbol] :> Dist[1/e, Subst[Int[(a + b*Log[c*
x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, n, p}, x]

Rule 2296

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.), x_Symbol] :> Simp[x*(a + b*Log[c*x^n])^p, x] - Dist[b*n*p, In
t[(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{a, b, c, n}, x] && GtQ[p, 0] && IntegerQ[2*p]

Rule 2295

Int[Log[(c_.)*(x_)^(n_.)], x_Symbol] :> Simp[x*Log[c*x^n], x] - Simp[n*x, x] /; FreeQ[{c, n}, x]

Rule 2396

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_)/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*
(f + g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n])^p)/g, x] - Dist[(b*e*n*p)/g, Int[(Log[(e*(f + g*x))/(e*f -
d*g)]*(a + b*Log[c*(d + e*x)^n])^(p - 1))/(d + e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && NeQ[e*
f - d*g, 0] && IGtQ[p, 1]

Rule 2433

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_.) + Log[(h_.)*((i_.) + (j_.)*(x_))^(m_.)]*
(g_.))*((k_.) + (l_.)*(x_))^(r_.), x_Symbol] :> Dist[1/e, Subst[Int[((k*x)/d)^r*(a + b*Log[c*x^n])^p*(f + g*Lo
g[h*((e*i - d*j)/e + (j*x)/e)^m]), x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, j, k, l, n, p, r},
x] && EqQ[e*k - d*l, 0]

Rule 2374

Int[(Log[(d_.)*((e_) + (f_.)*(x_)^(m_.))]*((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.))/(x_), x_Symbol] :> -Sim
p[(PolyLog[2, -(d*f*x^m)]*(a + b*Log[c*x^n])^p)/m, x] + Dist[(b*n*p)/m, Int[(PolyLog[2, -(d*f*x^m)]*(a + b*Log
[c*x^n])^(p - 1))/x, x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[p, 0] && EqQ[d*e, 1]

Rule 2383

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*PolyLog[k_, (e_.)*(x_)^(q_.)])/(x_), x_Symbol] :> Simp[(PolyL
og[k + 1, e*x^q]*(a + b*Log[c*x^n])^p)/q, x] - Dist[(b*n*p)/q, Int[(PolyLog[k + 1, e*x^q]*(a + b*Log[c*x^n])^(
p - 1))/x, x], x] /; FreeQ[{a, b, c, e, k, n, q}, x] && GtQ[p, 0]

Rule 6589

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rubi steps

\begin{align*} \int \frac{(h+230 x) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{f+g x} \, dx &=\int \left (\frac{230 \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{g}+\frac{(-230 f+g h) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{g (f+g x)}\right ) \, dx\\ &=\frac{230 \int \left (a+b \log \left (c (d+e x)^n\right )\right )^3 \, dx}{g}+\frac{(-230 f+g h) \int \frac{\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{f+g x} \, dx}{g}\\ &=-\frac{(230 f-g h) \left (a+b \log \left (c (d+e x)^n\right )\right )^3 \log \left (\frac{e (f+g x)}{e f-d g}\right )}{g^2}+\frac{230 \operatorname{Subst}\left (\int \left (a+b \log \left (c x^n\right )\right )^3 \, dx,x,d+e x\right )}{e g}+\frac{(3 b e (230 f-g h) n) \int \frac{\left (a+b \log \left (c (d+e x)^n\right )\right )^2 \log \left (\frac{e (f+g x)}{e f-d g}\right )}{d+e x} \, dx}{g^2}\\ &=\frac{230 (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{e g}-\frac{(230 f-g h) \left (a+b \log \left (c (d+e x)^n\right )\right )^3 \log \left (\frac{e (f+g x)}{e f-d g}\right )}{g^2}-\frac{(690 b n) \operatorname{Subst}\left (\int \left (a+b \log \left (c x^n\right )\right )^2 \, dx,x,d+e x\right )}{e g}+\frac{(3 b (230 f-g h) n) \operatorname{Subst}\left (\int \frac{\left (a+b \log \left (c x^n\right )\right )^2 \log \left (\frac{e \left (\frac{e f-d g}{e}+\frac{g x}{e}\right )}{e f-d g}\right )}{x} \, dx,x,d+e x\right )}{g^2}\\ &=-\frac{690 b n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{e g}+\frac{230 (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{e g}-\frac{(230 f-g h) \left (a+b \log \left (c (d+e x)^n\right )\right )^3 \log \left (\frac{e (f+g x)}{e f-d g}\right )}{g^2}-\frac{3 b (230 f-g h) n \left (a+b \log \left (c (d+e x)^n\right )\right )^2 \text{Li}_2\left (-\frac{g (d+e x)}{e f-d g}\right )}{g^2}+\frac{\left (1380 b^2 n^2\right ) \operatorname{Subst}\left (\int \left (a+b \log \left (c x^n\right )\right ) \, dx,x,d+e x\right )}{e g}+\frac{\left (6 b^2 (230 f-g h) n^2\right ) \operatorname{Subst}\left (\int \frac{\left (a+b \log \left (c x^n\right )\right ) \text{Li}_2\left (-\frac{g x}{e f-d g}\right )}{x} \, dx,x,d+e x\right )}{g^2}\\ &=\frac{1380 a b^2 n^2 x}{g}-\frac{690 b n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{e g}+\frac{230 (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{e g}-\frac{(230 f-g h) \left (a+b \log \left (c (d+e x)^n\right )\right )^3 \log \left (\frac{e (f+g x)}{e f-d g}\right )}{g^2}-\frac{3 b (230 f-g h) n \left (a+b \log \left (c (d+e x)^n\right )\right )^2 \text{Li}_2\left (-\frac{g (d+e x)}{e f-d g}\right )}{g^2}+\frac{6 b^2 (230 f-g h) n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \text{Li}_3\left (-\frac{g (d+e x)}{e f-d g}\right )}{g^2}+\frac{\left (1380 b^3 n^2\right ) \operatorname{Subst}\left (\int \log \left (c x^n\right ) \, dx,x,d+e x\right )}{e g}-\frac{\left (6 b^3 (230 f-g h) n^3\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3\left (-\frac{g x}{e f-d g}\right )}{x} \, dx,x,d+e x\right )}{g^2}\\ &=\frac{1380 a b^2 n^2 x}{g}-\frac{1380 b^3 n^3 x}{g}+\frac{1380 b^3 n^2 (d+e x) \log \left (c (d+e x)^n\right )}{e g}-\frac{690 b n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{e g}+\frac{230 (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^3}{e g}-\frac{(230 f-g h) \left (a+b \log \left (c (d+e x)^n\right )\right )^3 \log \left (\frac{e (f+g x)}{e f-d g}\right )}{g^2}-\frac{3 b (230 f-g h) n \left (a+b \log \left (c (d+e x)^n\right )\right )^2 \text{Li}_2\left (-\frac{g (d+e x)}{e f-d g}\right )}{g^2}+\frac{6 b^2 (230 f-g h) n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \text{Li}_3\left (-\frac{g (d+e x)}{e f-d g}\right )}{g^2}-\frac{6 b^3 (230 f-g h) n^3 \text{Li}_4\left (-\frac{g (d+e x)}{e f-d g}\right )}{g^2}\\ \end{align*}

Mathematica [B]  time = 0.378134, size = 799, normalized size = 2.59 \[ \frac{b^3 e g h \left (\log \left (\frac{e (f+g x)}{e f-d g}\right ) \log ^3(d+e x)+3 \text{PolyLog}\left (2,\frac{g (d+e x)}{d g-e f}\right ) \log ^2(d+e x)-6 \text{PolyLog}\left (3,\frac{g (d+e x)}{d g-e f}\right ) \log (d+e x)+6 \text{PolyLog}\left (4,\frac{g (d+e x)}{d g-e f}\right )\right ) n^3-b^3 i \left (g \left (-(d+e x) \log ^3(d+e x)+3 (d+e x) \log ^2(d+e x)-6 (d+e x) \log (d+e x)+6 e x\right )+e f \left (\log \left (\frac{e (f+g x)}{e f-d g}\right ) \log ^3(d+e x)+3 \text{PolyLog}\left (2,\frac{g (d+e x)}{d g-e f}\right ) \log ^2(d+e x)-6 \text{PolyLog}\left (3,\frac{g (d+e x)}{d g-e f}\right ) \log (d+e x)+6 \text{PolyLog}\left (4,\frac{g (d+e x)}{d g-e f}\right )\right )\right ) n^3+3 b^2 i \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right ) \left (g \left ((d+e x) \log ^2(d+e x)-2 (d+e x) \log (d+e x)+2 e x\right )-e f \left (\log \left (\frac{e (f+g x)}{e f-d g}\right ) \log ^2(d+e x)+2 \text{PolyLog}\left (2,\frac{g (d+e x)}{d g-e f}\right ) \log (d+e x)-2 \text{PolyLog}\left (3,\frac{g (d+e x)}{d g-e f}\right )\right )\right ) n^2+6 b^2 e g h \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right ) \left (\frac{1}{2} \log \left (\frac{e (f+g x)}{e f-d g}\right ) \log ^2(d+e x)+\text{PolyLog}\left (2,\frac{g (d+e x)}{d g-e f}\right ) \log (d+e x)-\text{PolyLog}\left (3,\frac{g (d+e x)}{d g-e f}\right )\right ) n^2+3 b e g h \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2 \left (\log (d+e x) \log \left (\frac{e (f+g x)}{e f-d g}\right )+\text{PolyLog}\left (2,\frac{g (d+e x)}{d g-e f}\right )\right ) n-3 b i \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2 \left (e f \left (\log (d+e x) \log \left (\frac{e (f+g x)}{e f-d g}\right )+\text{PolyLog}\left (2,\frac{g (d+e x)}{d g-e f}\right )\right )-g (d+e x) (\log (d+e x)-1)\right ) n+e g i x \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^3+e (g h-f i) \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^3 \log (f+g x)}{e g^2} \]

Antiderivative was successfully verified.

[In]

Integrate[((h + i*x)*(a + b*Log[c*(d + e*x)^n])^3)/(f + g*x),x]

[Out]

(e*g*i*x*(a - b*n*Log[d + e*x] + b*Log[c*(d + e*x)^n])^3 + e*(g*h - f*i)*(a - b*n*Log[d + e*x] + b*Log[c*(d +
e*x)^n])^3*Log[f + g*x] + 3*b*e*g*h*n*(a - b*n*Log[d + e*x] + b*Log[c*(d + e*x)^n])^2*(Log[d + e*x]*Log[(e*(f
+ g*x))/(e*f - d*g)] + PolyLog[2, (g*(d + e*x))/(-(e*f) + d*g)]) - 3*b*i*n*(a - b*n*Log[d + e*x] + b*Log[c*(d
+ e*x)^n])^2*(-(g*(d + e*x)*(-1 + Log[d + e*x])) + e*f*(Log[d + e*x]*Log[(e*(f + g*x))/(e*f - d*g)] + PolyLog[
2, (g*(d + e*x))/(-(e*f) + d*g)])) + 3*b^2*i*n^2*(a - b*n*Log[d + e*x] + b*Log[c*(d + e*x)^n])*(g*(2*e*x - 2*(
d + e*x)*Log[d + e*x] + (d + e*x)*Log[d + e*x]^2) - e*f*(Log[d + e*x]^2*Log[(e*(f + g*x))/(e*f - d*g)] + 2*Log
[d + e*x]*PolyLog[2, (g*(d + e*x))/(-(e*f) + d*g)] - 2*PolyLog[3, (g*(d + e*x))/(-(e*f) + d*g)])) + 6*b^2*e*g*
h*n^2*(a - b*n*Log[d + e*x] + b*Log[c*(d + e*x)^n])*((Log[d + e*x]^2*Log[(e*(f + g*x))/(e*f - d*g)])/2 + Log[d
+ e*x]*PolyLog[2, (g*(d + e*x))/(-(e*f) + d*g)] - PolyLog[3, (g*(d + e*x))/(-(e*f) + d*g)]) + b^3*e*g*h*n^3*(
Log[d + e*x]^3*Log[(e*(f + g*x))/(e*f - d*g)] + 3*Log[d + e*x]^2*PolyLog[2, (g*(d + e*x))/(-(e*f) + d*g)] - 6*
Log[d + e*x]*PolyLog[3, (g*(d + e*x))/(-(e*f) + d*g)] + 6*PolyLog[4, (g*(d + e*x))/(-(e*f) + d*g)]) - b^3*i*n^
3*(g*(6*e*x - 6*(d + e*x)*Log[d + e*x] + 3*(d + e*x)*Log[d + e*x]^2 - (d + e*x)*Log[d + e*x]^3) + e*f*(Log[d +
e*x]^3*Log[(e*(f + g*x))/(e*f - d*g)] + 3*Log[d + e*x]^2*PolyLog[2, (g*(d + e*x))/(-(e*f) + d*g)] - 6*Log[d +
e*x]*PolyLog[3, (g*(d + e*x))/(-(e*f) + d*g)] + 6*PolyLog[4, (g*(d + e*x))/(-(e*f) + d*g)])))/(e*g^2)

________________________________________________________________________________________

Maple [F]  time = 2.141, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( ix+h \right ) \left ( a+b\ln \left ( c \left ( ex+d \right ) ^{n} \right ) \right ) ^{3}}{gx+f}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((i*x+h)*(a+b*ln(c*(e*x+d)^n))^3/(g*x+f),x)

[Out]

int((i*x+h)*(a+b*ln(c*(e*x+d)^n))^3/(g*x+f),x)

________________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} a^{3} i{\left (\frac{x}{g} - \frac{f \log \left (g x + f\right )}{g^{2}}\right )} + \frac{a^{3} h \log \left (g x + f\right )}{g} + \int \frac{b^{3} h \log \left (c\right )^{3} + 3 \, a b^{2} h \log \left (c\right )^{2} + 3 \, a^{2} b h \log \left (c\right ) +{\left (b^{3} i x + b^{3} h\right )} \log \left ({\left (e x + d\right )}^{n}\right )^{3} + 3 \,{\left (b^{3} h \log \left (c\right ) + a b^{2} h +{\left (b^{3} i \log \left (c\right ) + a b^{2} i\right )} x\right )} \log \left ({\left (e x + d\right )}^{n}\right )^{2} +{\left (b^{3} i \log \left (c\right )^{3} + 3 \, a b^{2} i \log \left (c\right )^{2} + 3 \, a^{2} b i \log \left (c\right )\right )} x + 3 \,{\left (b^{3} h \log \left (c\right )^{2} + 2 \, a b^{2} h \log \left (c\right ) + a^{2} b h +{\left (b^{3} i \log \left (c\right )^{2} + 2 \, a b^{2} i \log \left (c\right ) + a^{2} b i\right )} x\right )} \log \left ({\left (e x + d\right )}^{n}\right )}{g x + f}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((i*x+h)*(a+b*log(c*(e*x+d)^n))^3/(g*x+f),x, algorithm="maxima")

[Out]

a^3*i*(x/g - f*log(g*x + f)/g^2) + a^3*h*log(g*x + f)/g + integrate((b^3*h*log(c)^3 + 3*a*b^2*h*log(c)^2 + 3*a
^2*b*h*log(c) + (b^3*i*x + b^3*h)*log((e*x + d)^n)^3 + 3*(b^3*h*log(c) + a*b^2*h + (b^3*i*log(c) + a*b^2*i)*x)
*log((e*x + d)^n)^2 + (b^3*i*log(c)^3 + 3*a*b^2*i*log(c)^2 + 3*a^2*b*i*log(c))*x + 3*(b^3*h*log(c)^2 + 2*a*b^2
*h*log(c) + a^2*b*h + (b^3*i*log(c)^2 + 2*a*b^2*i*log(c) + a^2*b*i)*x)*log((e*x + d)^n))/(g*x + f), x)

________________________________________________________________________________________

Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{a^{3} i x + a^{3} h +{\left (b^{3} i x + b^{3} h\right )} \log \left ({\left (e x + d\right )}^{n} c\right )^{3} + 3 \,{\left (a b^{2} i x + a b^{2} h\right )} \log \left ({\left (e x + d\right )}^{n} c\right )^{2} + 3 \,{\left (a^{2} b i x + a^{2} b h\right )} \log \left ({\left (e x + d\right )}^{n} c\right )}{g x + f}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((i*x+h)*(a+b*log(c*(e*x+d)^n))^3/(g*x+f),x, algorithm="fricas")

[Out]

integral((a^3*i*x + a^3*h + (b^3*i*x + b^3*h)*log((e*x + d)^n*c)^3 + 3*(a*b^2*i*x + a*b^2*h)*log((e*x + d)^n*c
)^2 + 3*(a^2*b*i*x + a^2*b*h)*log((e*x + d)^n*c))/(g*x + f), x)

________________________________________________________________________________________

Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (a + b \log{\left (c \left (d + e x\right )^{n} \right )}\right )^{3} \left (h + i x\right )}{f + g x}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((i*x+h)*(a+b*ln(c*(e*x+d)**n))**3/(g*x+f),x)

[Out]

Integral((a + b*log(c*(d + e*x)**n))**3*(h + i*x)/(f + g*x), x)

________________________________________________________________________________________

Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (i x + h\right )}{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{3}}{g x + f}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((i*x+h)*(a+b*log(c*(e*x+d)^n))^3/(g*x+f),x, algorithm="giac")

[Out]

integrate((i*x + h)*(b*log((e*x + d)^n*c) + a)^3/(g*x + f), x)